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	<title>Comments on: What are const rvalue references good for?</title>
	<link>https://codesynthesis.com/~boris/blog//2012/07/24/const-rvalue-references/</link>
	<description>Boris Kolpackov's blog about software</description>
	<pubDate>Wed, 22 Apr 2026 02:35:39 +0000</pubDate>
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		<title>By: Boris Kolpackov</title>
		<link>https://codesynthesis.com/~boris/blog//2012/07/24/const-rvalue-references/#comment-2227</link>
		<author>Boris Kolpackov</author>
		<pubDate>Thu, 26 Jul 2012 14:51:14 +0000</pubDate>
		<guid>https://codesynthesis.com/~boris/blog//2012/07/24/const-rvalue-references/#comment-2227</guid>
		<description>Pizer, yes, you are correct. I've updated the examples in the post to use a class-type instead of int. Thanks for pointing this out.</description>
		<content:encoded><![CDATA[<p>Pizer, yes, you are correct. I&#8217;ve updated the examples in the post to use a class-type instead of int. Thanks for pointing this out.</p>
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		<title>By: pizer</title>
		<link>https://codesynthesis.com/~boris/blog//2012/07/24/const-rvalue-references/#comment-2225</link>
		<author>pizer</author>
		<pubDate>Wed, 25 Jul 2012 22:06:40 +0000</pubDate>
		<guid>https://codesynthesis.com/~boris/blog//2012/07/24/const-rvalue-references/#comment-2225</guid>
		<description>There are no const prvalues of scalar types. For a const rvalue you either need an Xvalue and/or a class-type object. I'm almost sure that a conforming compiler would treat f(g()) just like f(1) in terms of overload resolution since g just returns a value and not an object.</description>
		<content:encoded><![CDATA[<p>There are no const prvalues of scalar types. For a const rvalue you either need an Xvalue and/or a class-type object. I&#8217;m almost sure that a conforming compiler would treat f(g()) just like f(1) in terms of overload resolution since g just returns a value and not an object.</p>
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