[xsd-users] reading simple_type

[Boris Kolpackov]

Hi Nick,

Nick Hunter <nickhunteur at gmail.com> writes:

> The " <xsd:attribute name="StartUp" use="required" /> " schema definition
> has not been declared with a 'type' and so the StartUp member of the Feature
> class is an ::xml_schema::simple_type in the tree.
> 
> The problem I have run into is how to read the value "RenderingRootFeature"
> from the StartUp and Alias attributes. Is there a way to read a std::string
> from the ::xml_schema::simple_type?

No, not directly. In XML Schema, anySimpleType (which is mapped to 
xml_schema::simple_type) is a base type for all simple types so we
cannot always store a "raw" representation there since the overhead
would be too high (as a side note, in the next major release of
XSD we are planning to re-design this implementation and map
anySimpleType to two types: simple_type which will still be a, now
abstract, base for all simple types and any_simple_type which will
be used for attributes/elements that use anySimpleType; the
any_simple_type type will have a string member containing the 
raw data).

For now, there are two way to work around this. The simplest would 
be to modify your schema and add type="xsd:string" to all the attributes
that miss the type declaration.

The other approach is a bit more complicated and involves customizing
xml_schema::simple_type. The advantage of this method is the ability
to use the schema without any modifications. The following post
describes how to do this (it talks about xml_schema::type but this
also applies to xml_schema::simple_type):

http://www.codesynthesis.com/pipermail/xsd-users/2009-October/002492.html

Boris